Help with Genetics homework please!!!?

A true-breeding line peas with purple flowers, yellow pods, axial flowers, and green seeds (line A), is crossed to a true-breeding line with white flowers, green pods, and terminal flowers, and yellow seeds. The F1all have purple flowers, green pods, terminal flowers, and yellow seeds.



How many loci involved in this cross?

A typical line A individual would exhibit how many different pollen genotypes?

How many types of gametes can the F1 plants make?

How many of the F2 are expected to exhibit all four recessive traits?



I know that this is extremely long but any help will do. Please keep all unrelated answers to urself. Thanks in advance

Help with Genetics homework please!!!?
First, note the word "true-breeding". That indicates each plant is homozygous for all those traits, which means that you don't have to worry about that plant being het for any of those genes. And it means that they only make a single kind of gamete with regard to thsoe 4 genes.



Technically, these loci might all be linked to each other, you would need F2 data to know for sure. But you are supposed to assume that four traits are controlled by 4 genes.



Now, since the parents were homozygous for all their genotypes, the offspring will all be identical, they will all be het for those genotypes. And which ever phenotype they are, that's the dominant one for that trait. So purple, green, terminal, and yellow are the dominant phenotypes.



And there are 16 different gametes to be made, because there are 4 genes (presumably) and each is het in the F1.



The only way for an F2 to show all 4 recessive phenotypes would be for it to get a gamete from each parent taht also had all four recessive alleles. So 1 in16 gametes will fit the bill, so the odds of getting that gamete from on parent is 1 in 16, the odds of getting it from the other parent is 1/16, so the odds of getting it from both is 1/256.